-16x^2+33x+2=0

Solution for -16x^2+33x+2=0 equation:

-16x^2+33x+2=0

a = -16; b = 33; c = +2;
Δ = b2-4ac
Δ = 332-4·(-16)·2
Δ = 1217
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(33)-\sqrt{1217}}{2*-16}=\frac{-33-\sqrt{1217}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(33)+\sqrt{1217}}{2*-16}=\frac{-33+\sqrt{1217}}{-32}
$